$result = mysql_query("SELECT * FROM firma",$db); $myrow = mysql_fetch_array($result);
echo $myrow["name"];
?>
</body> </html>
Вот текст ошибки:
Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'Alex'@'127.0.0.1' (using password: YES) in C:\OpenServer\domains\localhost\php\mysql.php on line 12
Warning: mysql_select_db(): supplied argument is not a valid MySQL-Link resource in C:\OpenServer\domains\localhost\php\mysql.php on line 13
Warning: mysql_query(): supplied argument is not a valid MySQL-Link resource in C:\OpenServer\domains\localhost\php\mysql.php on line 15
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in C:\OpenServer\domains\localhost\php\mysql.php on line 16
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Здравствуйте, подскажите какой тег использовать для увеличения значения, пример на картинке.
Вроде, про такой тег я слышала. Если есть тег прогресс бар, значит и такое должно быть.
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ELBegemotos
Всем привет.Почему-то на локальном хосте не выводит данные из таблицы.
Вот код:
Вот текст ошибки:
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